(2x^2+3)/(4x-1)

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Solution for (2x^2+3)/(4x-1) equation: 


D( x )

4*x-1 = 0

4*x-1 = 0

4*x-1 = 0

4*x-1 = 0 // + 1

4*x = 1 // : 4

x = 1/4

x in (-oo:1/4) U (1/4:+oo)

(2*x^2+3)/(4*x-1) = 0

2*x^2 = -3 // : 2

x^2 = -3/2

x belongs to the empty set

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